x+(2x-7)/2-(3x+1)/5=5-(x+6)/2

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Solution for x+(2x-7)/2-(3x+1)/5=5-(x+6)/2 equation: 



x+(2x-7)/2-(3x+1)/5=5-(x+6)/2

We move all terms to the left:

x+(2x-7)/2-(3x+1)/5-(5-(x+6)/2)=0

We calculate fractions


x+(10x-35)/()+(-3x)/()+(-(5-(x+6)*5)/()=0



We calculate terms in parentheses: +(-(5-(x+6)*5)/(), so:

-(5-(x+6)*5)/(

We multiply all the terms by the denominator


-(5-(x+6)*5)



We calculate terms in parentheses: -(5-(x+6)*5), so:

5-(x+6)*5

determiningTheFunctionDomain
-(x+6)*5+5

We multiply parentheses

-5x-30+5

We add all the numbers together, and all the variables

-5x-25

Back to the equation:

-(-5x-25)



We get rid of parentheses

5x+25

Back to the equation:

+(5x+25)



We get rid of parentheses

x+(10x-35)/()+(-3x)/()+5x+25=0

We multiply all the terms by the denominator


x*()+(10x-35)+(-3x)+5x*()+25*()=0

We add all the numbers together, and all the variables

x*()+(10x-35)+(-3x)+5x*()=0

We get rid of parentheses

x*()+10x-3x+5x*()-35=0

We add all the numbers together, and all the variables

7x+x*()+5x*()-35=0

We move all terms containing x to the left, all other terms to the right

7x+x*()+5x*()=35

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