x+(2x/3)+(8x/3)=936

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Solution for x+(2x/3)+(8x/3)=936 equation: 



x+(2x/3)+(8x/3)=936

We move all terms to the left:

x+(2x/3)+(8x/3)-(936)=0

We add all the numbers together, and all the variables

x+(+2x/3)+(+8x/3)-936=0

We get rid of parentheses

x+2x/3+8x/3-936=0

We multiply all the terms by the denominator


x*3+2x+8x-936*3=0

We add all the numbers together, and all the variables

10x+x*3-2808=0

Wy multiply elements

10x+3x-2808=0

We add all the numbers together, and all the variables

13x-2808=0

We move all terms containing x to the left, all other terms to the right

13x=2808

x=2808/13

x=216

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