x+(2x2)+(2x2)=180

Solution for x+(2x2)+(2x2)=180 equation:

x+(2x^2)+(2x^2)=180

We move all terms to the left:

x+(2x^2)+(2x^2)-(180)=0

determiningTheFunctionDomain
2x^2+2x^2+x-180=0

We add all the numbers together, and all the variables

4x^2+x-180=0

a = 4; b = 1; c = -180;
Δ = b2-4ac
Δ = 12-4·4·(-180)
Δ = 2881
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{2881}}{2*4}=\frac{-1-\sqrt{2881}}{8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{2881}}{2*4}=\frac{-1+\sqrt{2881}}{8}
$