x+(3/4x)=14

Solution for x+(3/4x)=14 equation:

x+(3/4x)=14

We move all terms to the left:

x+(3/4x)-(14)=0


Domain of the equation: 4x)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

x+(+3/4x)-14=0

We get rid of parentheses

x+3/4x-14=0

We multiply all the terms by the denominator


x*4x-14*4x+3=0

Wy multiply elements

4x^2-56x+3=0

a = 4; b = -56; c = +3;
Δ = b2-4ac
Δ = -562-4·4·3
Δ = 3088
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{3088}=\sqrt{16*193}=\sqrt{16}*\sqrt{193}=4\sqrt{193}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-56)-4\sqrt{193}}{2*4}=\frac{56-4\sqrt{193}}{8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-56)+4\sqrt{193}}{2*4}=\frac{56+4\sqrt{193}}{8}
$