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x+(3/8)x=77
We move all terms to the left:
x+(3/8)x-(77)=0
Domain of the equation: 8)x!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
x+(+3/8)x-77=0
We multiply parentheses
3x^2+x-77=0
a = 3; b = 1; c = -77;
Δ = b2-4ac
Δ = 12-4·3·(-77)
Δ = 925
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{925}=\sqrt{25*37}=\sqrt{25}*\sqrt{37}=5\sqrt{37}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-5\sqrt{37}}{2*3}=\frac{-1-5\sqrt{37}}{6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+5\sqrt{37}}{2*3}=\frac{-1+5\sqrt{37}}{6} $
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