x+(3X)+(3x-20)=120

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Solution for x+(3X)+(3x-20)=120 equation: 



x+(3x)+(3x-20)=120

We move all terms to the left:

x+(3x)+(3x-20)-(120)=0

We add all the numbers together, and all the variables

4x+(3x-20)-120=0

We get rid of parentheses

4x+3x-20-120=0

We add all the numbers together, and all the variables

7x-140=0

We move all terms containing x to the left, all other terms to the right

7x=140

x=140/7

x=20

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