x+(3x+-16)=200

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Solution for x+(3x+-16)=200 equation: 



x+(3x+-16)=200

We move all terms to the left:

x+(3x+-16)-(200)=0

We add all the numbers together, and all the variables

x+(3x-16)-200=0

We get rid of parentheses

x+3x-16-200=0

We add all the numbers together, and all the variables

4x-216=0

We move all terms containing x to the left, all other terms to the right

4x=216

x=216/4

x=54

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