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x+(3x+20)+2(3x+15)=1010
We move all terms to the left:
x+(3x+20)+2(3x+15)-(1010)=0
We multiply parentheses
x+(3x+20)+6x+30-1010=0
We get rid of parentheses
x+3x+6x+20+30-1010=0
We add all the numbers together, and all the variables
10x-960=0
We move all terms containing x to the left, all other terms to the right
10x=960
x=960/10
x=96
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