x+(3x+3)+(3x-1)=16

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Solution for x+(3x+3)+(3x-1)=16 equation: 



x+(3x+3)+(3x-1)=16

We move all terms to the left:

x+(3x+3)+(3x-1)-(16)=0

We get rid of parentheses

x+3x+3x+3-1-16=0

We add all the numbers together, and all the variables

7x-14=0

We move all terms containing x to the left, all other terms to the right

7x=14

x=14/7

x=2

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