x+(3x-2x)=18

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Solution for x+(3x-2x)=18 equation: 



x+(3x-2x)=18

We move all terms to the left:

x+(3x-2x)-(18)=0

We add all the numbers together, and all the variables

x+(+x)-18=0

We get rid of parentheses

x+x-18=0

We add all the numbers together, and all the variables

2x-18=0

We move all terms containing x to the left, all other terms to the right

2x=18

x=18/2

x=9

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