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x+(3x-7)=4x-(x+2)
We move all terms to the left:
x+(3x-7)-(4x-(x+2))=0
We get rid of parentheses
x+3x-(4x-(x+2))-7=0
We calculate terms in parentheses: -(4x-(x+2)), so:We add all the numbers together, and all the variables
4x-(x+2)
We get rid of parentheses
4x-x-2
We add all the numbers together, and all the variables
3x-2
Back to the equation:
-(3x-2)
4x-(3x-2)-7=0
We get rid of parentheses
4x-3x+2-7=0
We add all the numbers together, and all the variables
x-5=0
We move all terms containing x to the left, all other terms to the right
x=5
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