x+(3x/2)=20

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Solution for x+(3x/2)=20 equation: 



x+(3x/2)=20

We move all terms to the left:

x+(3x/2)-(20)=0

We add all the numbers together, and all the variables

x+(+3x/2)-20=0

We get rid of parentheses

x+3x/2-20=0

We multiply all the terms by the denominator


x*2+3x-20*2=0

We add all the numbers together, and all the variables

3x+x*2-40=0

Wy multiply elements

3x+2x-40=0

We add all the numbers together, and all the variables

5x-40=0

We move all terms containing x to the left, all other terms to the right

5x=40

x=40/5

x=8

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