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x+(4-x)=5(x+1)+x
We move all terms to the left:
x+(4-x)-(5(x+1)+x)=0
We add all the numbers together, and all the variables
x+(-1x+4)-(5(x+1)+x)=0
We get rid of parentheses
x-1x-(5(x+1)+x)+4=0
We calculate terms in parentheses: -(5(x+1)+x), so:We add all the numbers together, and all the variables
5(x+1)+x
We add all the numbers together, and all the variables
x+5(x+1)
We multiply parentheses
x+5x+5
We add all the numbers together, and all the variables
6x+5
Back to the equation:
-(6x+5)
-(6x+5)+4=0
We get rid of parentheses
-6x-5+4=0
We add all the numbers together, and all the variables
-6x-1=0
We move all terms containing x to the left, all other terms to the right
-6x=1
x=1/-6
x=-1/6
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