x+(4/3)x=28

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Solution for x+(4/3)x=28 equation:



x+(4/3)x=28
We move all terms to the left:
x+(4/3)x-(28)=0
Domain of the equation: 3)x!=0
x!=0/1
x!=0
x∈R
We add all the numbers together, and all the variables
x+(+4/3)x-28=0
We multiply parentheses
4x^2+x-28=0
a = 4; b = 1; c = -28;
Δ = b2-4ac
Δ = 12-4·4·(-28)
Δ = 449
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{449}}{2*4}=\frac{-1-\sqrt{449}}{8} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{449}}{2*4}=\frac{-1+\sqrt{449}}{8} $

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