x+(4/3x)=49

Solution for x+(4/3x)=49 equation:

x+(4/3x)=49

We move all terms to the left:

x+(4/3x)-(49)=0


Domain of the equation: 3x)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

x+(+4/3x)-49=0

We get rid of parentheses

x+4/3x-49=0

We multiply all the terms by the denominator


x*3x-49*3x+4=0

Wy multiply elements

3x^2-147x+4=0

a = 3; b = -147; c = +4;
Δ = b2-4ac
Δ = -1472-4·3·4
Δ = 21561
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-147)-\sqrt{21561}}{2*3}=\frac{147-\sqrt{21561}}{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-147)+\sqrt{21561}}{2*3}=\frac{147+\sqrt{21561}}{6}
$