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x+(5x)+(4x-19)=180
We move all terms to the left:
x+(5x)+(4x-19)-(180)=0
We add all the numbers together, and all the variables
6x+(4x-19)-180=0
We get rid of parentheses
6x+4x-19-180=0
We add all the numbers together, and all the variables
10x-199=0
We move all terms containing x to the left, all other terms to the right
10x=199
x=199/10
x=19+9/10
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