x+(6-x)+18=10(6-x)+x

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Solution for x+(6-x)+18=10(6-x)+x equation: 



x+(6-x)+18=10(6-x)+x

We move all terms to the left:

x+(6-x)+18-(10(6-x)+x)=0

We add all the numbers together, and all the variables

x+(-1x+6)-(10(-1x+6)+x)+18=0

We get rid of parentheses

x-1x-(10(-1x+6)+x)+6+18=0



We calculate terms in parentheses: -(10(-1x+6)+x), so:

10(-1x+6)+x

We add all the numbers together, and all the variables

x+10(-1x+6)

We multiply parentheses

x-10x+60

We add all the numbers together, and all the variables

-9x+60

Back to the equation:

-(-9x+60)



We add all the numbers together, and all the variables

-(-9x+60)+24=0

We get rid of parentheses

9x-60+24=0

We add all the numbers together, and all the variables

9x-36=0

We move all terms containing x to the left, all other terms to the right

9x=36

x=36/9

x=4

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