x+(8/11x)=76

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Solution for x+(8/11x)=76 equation:



x+(8/11x)=76
We move all terms to the left:
x+(8/11x)-(76)=0
Domain of the equation: 11x)!=0
x!=0/1
x!=0
x∈R
We add all the numbers together, and all the variables
x+(+8/11x)-76=0
We get rid of parentheses
x+8/11x-76=0
We multiply all the terms by the denominator
x*11x-76*11x+8=0
Wy multiply elements
11x^2-836x+8=0
a = 11; b = -836; c = +8;
Δ = b2-4ac
Δ = -8362-4·11·8
Δ = 698544
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{698544}=\sqrt{63504*11}=\sqrt{63504}*\sqrt{11}=252\sqrt{11}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-836)-252\sqrt{11}}{2*11}=\frac{836-252\sqrt{11}}{22} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-836)+252\sqrt{11}}{2*11}=\frac{836+252\sqrt{11}}{22} $

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