x+(8x/100x)=2000

Solution for x+(8x/100x)=2000 equation:

x+(8x/100x)=2000

We move all terms to the left:

x+(8x/100x)-(2000)=0


Domain of the equation: 100x)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

x+(+8x/100x)-2000=0

We get rid of parentheses

x+8x/100x-2000=0

We multiply all the terms by the denominator


x*100x+8x-2000*100x=0

We add all the numbers together, and all the variables

8x+x*100x-2000*100x=0

Wy multiply elements

100x^2+8x-200000x=0

We add all the numbers together, and all the variables

100x^2-199992x=0

a = 100; b = -199992; c = 0;
Δ = b2-4ac
Δ = -1999922-4·100·0
Δ = 39996800064
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{39996800064}=199992$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-199992)-199992}{2*100}=\frac{0}{200}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-199992)+199992}{2*100}=\frac{399984}{200}
=1999+23/25
$