x+(x+1)+(x+2)+(x+3)=248

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Solution for x+(x+1)+(x+2)+(x+3)=248 equation: 



x+(x+1)+(x+2)+(x+3)=248

We move all terms to the left:

x+(x+1)+(x+2)+(x+3)-(248)=0

We get rid of parentheses

x+x+x+x+1+2+3-248=0

We add all the numbers together, and all the variables

4x-242=0

We move all terms containing x to the left, all other terms to the right

4x=242

x=242/4

x=60+1/2

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