x+(x+1)+(x+2)+(x+3)=4x

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Solution for x+(x+1)+(x+2)+(x+3)=4x equation:


Simplifying
x + (x + 1) + (x + 2) + (x + 3) = 4x

Reorder the terms:
x + (1 + x) + (x + 2) + (x + 3) = 4x

Remove parenthesis around (1 + x)
x + 1 + x + (x + 2) + (x + 3) = 4x

Reorder the terms:
x + 1 + x + (2 + x) + (x + 3) = 4x

Remove parenthesis around (2 + x)
x + 1 + x + 2 + x + (x + 3) = 4x

Reorder the terms:
x + 1 + x + 2 + x + (3 + x) = 4x

Remove parenthesis around (3 + x)
x + 1 + x + 2 + x + 3 + x = 4x

Reorder the terms:
1 + 2 + 3 + x + x + x + x = 4x

Combine like terms: 1 + 2 = 3
3 + 3 + x + x + x + x = 4x

Combine like terms: 3 + 3 = 6
6 + x + x + x + x = 4x

Combine like terms: x + x = 2x
6 + 2x + x + x = 4x

Combine like terms: 2x + x = 3x
6 + 3x + x = 4x

Combine like terms: 3x + x = 4x
6 + 4x = 4x

Add '-4x' to each side of the equation.
6 + 4x + -4x = 4x + -4x

Combine like terms: 4x + -4x = 0
6 + 0 = 4x + -4x
6 = 4x + -4x

Combine like terms: 4x + -4x = 0
6 = 0

Solving
6 = 0

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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