x+(x+1)+(x+2)+(x+3)=568

Solution for x+(x+1)+(x+2)+(x+3)=568 equation:

Simplifying
x + (x + 1) + (x + 2) + (x + 3) = 568

Reorder the terms:
x + (1 + x) + (x + 2) + (x + 3) = 568

Remove parenthesis around (1 + x)
x + 1 + x + (x + 2) + (x + 3) = 568

Reorder the terms:
x + 1 + x + (2 + x) + (x + 3) = 568

Remove parenthesis around (2 + x)
x + 1 + x + 2 + x + (x + 3) = 568

Reorder the terms:
x + 1 + x + 2 + x + (3 + x) = 568

Remove parenthesis around (3 + x)
x + 1 + x + 2 + x + 3 + x = 568

Reorder the terms:
1 + 2 + 3 + x + x + x + x = 568

Combine like terms: 1 + 2 = 3
3 + 3 + x + x + x + x = 568

Combine like terms: 3 + 3 = 6
6 + x + x + x + x = 568

Combine like terms: x + x = 2x
6 + 2x + x + x = 568

Combine like terms: 2x + x = 3x
6 + 3x + x = 568

Combine like terms: 3x + x = 4x
6 + 4x = 568

Solving
6 + 4x = 568

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-6' to each side of the equation.
6 + -6 + 4x = 568 + -6

Combine like terms: 6 + -6 = 0
0 + 4x = 568 + -6
4x = 568 + -6

Combine like terms: 568 + -6 = 562
4x = 562

Divide each side by '4'.
x = 140.5

Simplifying
x = 140.5