x+(x+1)+(x+2)=128

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Solution for x+(x+1)+(x+2)=128 equation:


Simplifying
x + (x + 1) + (x + 2) = 128

Reorder the terms:
x + (1 + x) + (x + 2) = 128

Remove parenthesis around (1 + x)
x + 1 + x + (x + 2) = 128

Reorder the terms:
x + 1 + x + (2 + x) = 128

Remove parenthesis around (2 + x)
x + 1 + x + 2 + x = 128

Reorder the terms:
1 + 2 + x + x + x = 128

Combine like terms: 1 + 2 = 3
3 + x + x + x = 128

Combine like terms: x + x = 2x
3 + 2x + x = 128

Combine like terms: 2x + x = 3x
3 + 3x = 128

Solving
3 + 3x = 128

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-3' to each side of the equation.
3 + -3 + 3x = 128 + -3

Combine like terms: 3 + -3 = 0
0 + 3x = 128 + -3
3x = 128 + -3

Combine like terms: 128 + -3 = 125
3x = 125

Divide each side by '3'.
x = 41.66666667

Simplifying
x = 41.66666667

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