x+(x+1)+(x+2)=132

Solution for x+(x+1)+(x+2)=132 equation:

Simplifying
x + (x + 1) + (x + 2) = 132

Reorder the terms:
x + (1 + x) + (x + 2) = 132

Remove parenthesis around (1 + x)
x + 1 + x + (x + 2) = 132

Reorder the terms:
x + 1 + x + (2 + x) = 132

Remove parenthesis around (2 + x)
x + 1 + x + 2 + x = 132

Reorder the terms:
1 + 2 + x + x + x = 132

Combine like terms: 1 + 2 = 3
3 + x + x + x = 132

Combine like terms: x + x = 2x
3 + 2x + x = 132

Combine like terms: 2x + x = 3x
3 + 3x = 132

Solving
3 + 3x = 132

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-3' to each side of the equation.
3 + -3 + 3x = 132 + -3

Combine like terms: 3 + -3 = 0
0 + 3x = 132 + -3
3x = 132 + -3

Combine like terms: 132 + -3 = 129
3x = 129

Divide each side by '3'.
x = 43

Simplifying
x = 43