x+(x+1)+(x+2)=3x-3

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Solution for x+(x+1)+(x+2)=3x-3 equation:


Simplifying
x + (x + 1) + (x + 2) = 3x + -3

Reorder the terms:
x + (1 + x) + (x + 2) = 3x + -3

Remove parenthesis around (1 + x)
x + 1 + x + (x + 2) = 3x + -3

Reorder the terms:
x + 1 + x + (2 + x) = 3x + -3

Remove parenthesis around (2 + x)
x + 1 + x + 2 + x = 3x + -3

Reorder the terms:
1 + 2 + x + x + x = 3x + -3

Combine like terms: 1 + 2 = 3
3 + x + x + x = 3x + -3

Combine like terms: x + x = 2x
3 + 2x + x = 3x + -3

Combine like terms: 2x + x = 3x
3 + 3x = 3x + -3

Reorder the terms:
3 + 3x = -3 + 3x

Add '-3x' to each side of the equation.
3 + 3x + -3x = -3 + 3x + -3x

Combine like terms: 3x + -3x = 0
3 + 0 = -3 + 3x + -3x
3 = -3 + 3x + -3x

Combine like terms: 3x + -3x = 0
3 = -3 + 0
3 = -3

Solving
3 = -3

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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