x+(x+1)+(x+2)=48,x=

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Solution for x+(x+1)+(x+2)=48,x= equation: 



x+(x+1)+(x+2)=48.x=

We move all terms to the left:

x+(x+1)+(x+2)-(48.x)=0

We add all the numbers together, and all the variables

x+(x+1)+(x+2)-(+48.x)=0

We get rid of parentheses

x+x+x-48.x+1+2=0

We add all the numbers together, and all the variables

-45x+3=0

We move all terms containing x to the left, all other terms to the right

-45x=-3

x=-3/-45

x=1/15

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