x+(x+1)+(x+2)=48,x=

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Solution for x+(x+1)+(x+2)=48,x= equation:



x+(x+1)+(x+2)=48.x=
We move all terms to the left:
x+(x+1)+(x+2)-(48.x)=0
We add all the numbers together, and all the variables
x+(x+1)+(x+2)-(+48.x)=0
We get rid of parentheses
x+x+x-48.x+1+2=0
We add all the numbers together, and all the variables
-45x+3=0
We move all terms containing x to the left, all other terms to the right
-45x=-3
x=-3/-45
x=1/15

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