x+(x+1)+(x+3)=21

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Solution for x+(x+1)+(x+3)=21 equation:


Simplifying
x + (x + 1) + (x + 3) = 21

Reorder the terms:
x + (1 + x) + (x + 3) = 21

Remove parenthesis around (1 + x)
x + 1 + x + (x + 3) = 21

Reorder the terms:
x + 1 + x + (3 + x) = 21

Remove parenthesis around (3 + x)
x + 1 + x + 3 + x = 21

Reorder the terms:
1 + 3 + x + x + x = 21

Combine like terms: 1 + 3 = 4
4 + x + x + x = 21

Combine like terms: x + x = 2x
4 + 2x + x = 21

Combine like terms: 2x + x = 3x
4 + 3x = 21

Solving
4 + 3x = 21

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-4' to each side of the equation.
4 + -4 + 3x = 21 + -4

Combine like terms: 4 + -4 = 0
0 + 3x = 21 + -4
3x = 21 + -4

Combine like terms: 21 + -4 = 17
3x = 17

Divide each side by '3'.
x = 5.666666667

Simplifying
x = 5.666666667

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