x+(x+10)(x+5)=180

Solution for x+(x+10)(x+5)=180 equation:

x+(x+10)(x+5)=180

We move all terms to the left:

x+(x+10)(x+5)-(180)=0

We multiply parentheses ..

(+x^2+5x+10x+50)+x-180=0

We get rid of parentheses

x^2+5x+10x+x+50-180=0

We add all the numbers together, and all the variables

x^2+16x-130=0

a = 1; b = 16; c = -130;
Δ = b2-4ac
Δ = 162-4·1·(-130)
Δ = 776
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{776}=\sqrt{4*194}=\sqrt{4}*\sqrt{194}=2\sqrt{194}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(16)-2\sqrt{194}}{2*1}=\frac{-16-2\sqrt{194}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(16)+2\sqrt{194}}{2*1}=\frac{-16+2\sqrt{194}}{2}
$