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x+(x+15)=(x+120)
We move all terms to the left:
x+(x+15)-((x+120))=0
We get rid of parentheses
x+x-((x+120))+15=0
We calculate terms in parentheses: -((x+120)), so:We add all the numbers together, and all the variables
(x+120)
We get rid of parentheses
x+120
Back to the equation:
-(x+120)
2x-(x+120)+15=0
We get rid of parentheses
2x-x-120+15=0
We add all the numbers together, and all the variables
x-105=0
We move all terms containing x to the left, all other terms to the right
x=105
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