x+(x+2)+(x+3)+(x+4)=-282

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Solution for x+(x+2)+(x+3)+(x+4)=-282 equation: 



x+(x+2)+(x+3)+(x+4)=-282

We move all terms to the left:

x+(x+2)+(x+3)+(x+4)-(-282)=0

We add all the numbers together, and all the variables

x+(x+2)+(x+3)+(x+4)+282=0

We get rid of parentheses

x+x+x+x+2+3+4+282=0

We add all the numbers together, and all the variables

4x+291=0

We move all terms containing x to the left, all other terms to the right

4x=-291

x=-291/4

x=-72+3/4

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