x+(x+2)+(x+3)=122

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Solution for x+(x+2)+(x+3)=122 equation: 



x+(x+2)+(x+3)=122

We move all terms to the left:

x+(x+2)+(x+3)-(122)=0

We get rid of parentheses

x+x+x+2+3-122=0

We add all the numbers together, and all the variables

3x-117=0

We move all terms containing x to the left, all other terms to the right

3x=117

x=117/3

x=39

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