x+(x+2)+(x+4)/3=x/3+14

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Solution for x+(x+2)+(x+4)/3=x/3+14 equation: 



x+(x+2)+(x+4)/3=x/3+14

We move all terms to the left:

x+(x+2)+(x+4)/3-(x/3+14)=0

We get rid of parentheses

x+x+(x+4)/3-x/3+2-14=0

We multiply all the terms by the denominator


x*3+x*3+(x+4)-x+2*3-14*3=0

We add all the numbers together, and all the variables

-1x+x*3+x*3+(x+4)-36=0

Wy multiply elements

-1x+3x+3x+(x+4)-36=0

We get rid of parentheses

-1x+3x+3x+x+4-36=0

We add all the numbers together, and all the variables

6x-32=0

We move all terms containing x to the left, all other terms to the right

6x=32

x=32/6

x=5+1/3

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