x+(x+2)+(x+4)=12(x+2)+300

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Solution for x+(x+2)+(x+4)=12(x+2)+300 equation: 



x+(x+2)+(x+4)=12(x+2)+300

We move all terms to the left:

x+(x+2)+(x+4)-(12(x+2)+300)=0

We get rid of parentheses

x+x+x-(12(x+2)+300)+2+4=0



We calculate terms in parentheses: -(12(x+2)+300), so:

12(x+2)+300

We multiply parentheses

12x+24+300

We add all the numbers together, and all the variables

12x+324

Back to the equation:

-(12x+324)



We add all the numbers together, and all the variables

3x-(12x+324)+6=0

We get rid of parentheses

3x-12x-324+6=0

We add all the numbers together, and all the variables

-9x-318=0

We move all terms containing x to the left, all other terms to the right

-9x=318

x=318/-9

x=-35+1/3

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