x+(x+2)+(x+4)=22

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Solution for x+(x+2)+(x+4)=22 equation: 



x+(x+2)+(x+4)=22

We move all terms to the left:

x+(x+2)+(x+4)-(22)=0

We get rid of parentheses

x+x+x+2+4-22=0

We add all the numbers together, and all the variables

3x-16=0

We move all terms containing x to the left, all other terms to the right

3x=16

x=16/3

x=5+1/3

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