x+(x+2)+(x+4)=3(x+6)-2

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Solution for x+(x+2)+(x+4)=3(x+6)-2 equation:


Simplifying
x + (x + 2) + (x + 4) = 3(x + 6) + -2

Reorder the terms:
x + (2 + x) + (x + 4) = 3(x + 6) + -2

Remove parenthesis around (2 + x)
x + 2 + x + (x + 4) = 3(x + 6) + -2

Reorder the terms:
x + 2 + x + (4 + x) = 3(x + 6) + -2

Remove parenthesis around (4 + x)
x + 2 + x + 4 + x = 3(x + 6) + -2

Reorder the terms:
2 + 4 + x + x + x = 3(x + 6) + -2

Combine like terms: 2 + 4 = 6
6 + x + x + x = 3(x + 6) + -2

Combine like terms: x + x = 2x
6 + 2x + x = 3(x + 6) + -2

Combine like terms: 2x + x = 3x
6 + 3x = 3(x + 6) + -2

Reorder the terms:
6 + 3x = 3(6 + x) + -2
6 + 3x = (6 * 3 + x * 3) + -2
6 + 3x = (18 + 3x) + -2

Reorder the terms:
6 + 3x = 18 + -2 + 3x

Combine like terms: 18 + -2 = 16
6 + 3x = 16 + 3x

Add '-3x' to each side of the equation.
6 + 3x + -3x = 16 + 3x + -3x

Combine like terms: 3x + -3x = 0
6 + 0 = 16 + 3x + -3x
6 = 16 + 3x + -3x

Combine like terms: 3x + -3x = 0
6 = 16 + 0
6 = 16

Solving
6 = 16

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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