x+(x+2)=3(x+4)-27

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Solution for x+(x+2)=3(x+4)-27 equation: 



x+(x+2)=3(x+4)-27

We move all terms to the left:

x+(x+2)-(3(x+4)-27)=0

We get rid of parentheses

x+x-(3(x+4)-27)+2=0



We calculate terms in parentheses: -(3(x+4)-27), so:

3(x+4)-27

We multiply parentheses

3x+12-27

We add all the numbers together, and all the variables

3x-15

Back to the equation:

-(3x-15)



We add all the numbers together, and all the variables

2x-(3x-15)+2=0

We get rid of parentheses

2x-3x+15+2=0

We add all the numbers together, and all the variables

-1x+17=0

We move all terms containing x to the left, all other terms to the right

-x=-17

x=-17/-1

x=+17

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