x+(x+2)=3(x+4)-27

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Solution for x+(x+2)=3(x+4)-27 equation:



x+(x+2)=3(x+4)-27
We move all terms to the left:
x+(x+2)-(3(x+4)-27)=0
We get rid of parentheses
x+x-(3(x+4)-27)+2=0
We calculate terms in parentheses: -(3(x+4)-27), so:
3(x+4)-27
We multiply parentheses
3x+12-27
We add all the numbers together, and all the variables
3x-15
Back to the equation:
-(3x-15)
We add all the numbers together, and all the variables
2x-(3x-15)+2=0
We get rid of parentheses
2x-3x+15+2=0
We add all the numbers together, and all the variables
-1x+17=0
We move all terms containing x to the left, all other terms to the right
-x=-17
x=-17/-1
x=+17

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