x+(x+3)(x+-3)=3+x(x+1)

Solution for x+(x+3)(x+-3)=3+x(x+1) equation:

x+(x+3)(x+-3)=3+x(x+1)

We move all terms to the left:

x+(x+3)(x+-3)-(3+x(x+1))=0

We add all the numbers together, and all the variables

x+(x+3)(x-3)-(3+x(x+1))=0

We use the square of the difference formula

x^2+x-(3+x(x+1))-9=0


We calculate terms in parentheses: -(3+x(x+1)), so:

3+x(x+1)

determiningTheFunctionDomain
x(x+1)+3

We multiply parentheses

x^2+x+3

Back to the equation:

-(x^2+x+3)


We get rid of parentheses

x^2-x^2+x-x-3-9=0

We add all the numbers together, and all the variables

-12!=0

There is no solution for this equation