x+(x+3)+(x+6)=141

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Solution for x+(x+3)+(x+6)=141 equation: 



x+(x+3)+(x+6)=141

We move all terms to the left:

x+(x+3)+(x+6)-(141)=0

We get rid of parentheses

x+x+x+3+6-141=0

We add all the numbers together, and all the variables

3x-132=0

We move all terms containing x to the left, all other terms to the right

3x=132

x=132/3

x=44

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