x+(x+3)+(x-7)=64

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Solution for x+(x+3)+(x-7)=64 equation: 



x+(x+3)+(x-7)=64

We move all terms to the left:

x+(x+3)+(x-7)-(64)=0

We get rid of parentheses

x+x+x+3-7-64=0

We add all the numbers together, and all the variables

3x-68=0

We move all terms containing x to the left, all other terms to the right

3x=68

x=68/3

x=22+2/3

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