x+(x+4)+(x+4)2=21

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Solution for x+(x+4)+(x+4)2=21 equation:


Simplifying
x + (x + 4) + (x + 4) * 2 = 21

Reorder the terms:
x + (4 + x) + (x + 4) * 2 = 21

Remove parenthesis around (4 + x)
x + 4 + x + (x + 4) * 2 = 21

Reorder the terms:
x + 4 + x + (4 + x) * 2 = 21

Reorder the terms for easier multiplication:
x + 4 + x + 2(4 + x) = 21
x + 4 + x + (4 * 2 + x * 2) = 21
x + 4 + x + (8 + 2x) = 21

Reorder the terms:
4 + 8 + x + x + 2x = 21

Combine like terms: 4 + 8 = 12
12 + x + x + 2x = 21

Combine like terms: x + x = 2x
12 + 2x + 2x = 21

Combine like terms: 2x + 2x = 4x
12 + 4x = 21

Solving
12 + 4x = 21

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-12' to each side of the equation.
12 + -12 + 4x = 21 + -12

Combine like terms: 12 + -12 = 0
0 + 4x = 21 + -12
4x = 21 + -12

Combine like terms: 21 + -12 = 9
4x = 9

Divide each side by '4'.
x = 2.25

Simplifying
x = 2.25

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