x+(x+4)=(x+2)-(x-8)

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Solution for x+(x+4)=(x+2)-(x-8) equation: 



x+(x+4)=(x+2)-(x-8)

We move all terms to the left:

x+(x+4)-((x+2)-(x-8))=0

We get rid of parentheses

x+x-((x+2)-(x-8))+4=0



We calculate terms in parentheses: -((x+2)-(x-8)), so:

(x+2)-(x-8)

We get rid of parentheses

x-x+2+8

We add all the numbers together, and all the variables

10

Back to the equation:

-(10)



We add all the numbers together, and all the variables

2x-6=0

We move all terms containing x to the left, all other terms to the right

2x=6

x=6/2

x=3

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