x+(x+5)+((x+5)-2)=18

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Solution for x+(x+5)+((x+5)-2)=18 equation: 



x+(x+5)+((x+5)-2)=18

We move all terms to the left:

x+(x+5)+((x+5)-2)-(18)=0

We get rid of parentheses

x+x+((x+5)-2)+5-18=0



We calculate terms in parentheses: +((x+5)-2), so:

(x+5)-2

We get rid of parentheses

x+5-2

We add all the numbers together, and all the variables

x+3

Back to the equation:

+(x+3)



We add all the numbers together, and all the variables

2x+(x+3)-13=0

We get rid of parentheses

2x+x+3-13=0

We add all the numbers together, and all the variables

3x-10=0

We move all terms containing x to the left, all other terms to the right

3x=10

x=10/3

x=3+1/3

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