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x+(x+6)4x=132
We move all terms to the left:
x+(x+6)4x-(132)=0
We multiply parentheses
4x^2+x+24x-132=0
We add all the numbers together, and all the variables
4x^2+25x-132=0
a = 4; b = 25; c = -132;
Δ = b2-4ac
Δ = 252-4·4·(-132)
Δ = 2737
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(25)-\sqrt{2737}}{2*4}=\frac{-25-\sqrt{2737}}{8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(25)+\sqrt{2737}}{2*4}=\frac{-25+\sqrt{2737}}{8} $
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