x+(x-1)(x+5)+3x=3x+x

Solution for x+(x-1)(x+5)+3x=3x+x equation:

x+(x-1)(x+5)+3x=3x+x

We move all terms to the left:

x+(x-1)(x+5)+3x-(3x+x)=0

We add all the numbers together, and all the variables

x+(x-1)(x+5)+3x-(+4x)=0

We add all the numbers together, and all the variables

4x+(x-1)(x+5)-(+4x)=0

We get rid of parentheses

4x+(x-1)(x+5)-4x=0

We multiply parentheses ..

(+x^2+5x-1x-5)+4x-4x=0

We add all the numbers together, and all the variables

(+x^2+5x-1x-5)=0

We get rid of parentheses

x^2+5x-1x-5=0

We add all the numbers together, and all the variables

x^2+4x-5=0

a = 1; b = 4; c = -5;
Δ = b2-4ac
Δ = 42-4·1·(-5)
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{36}=6$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-6}{2*1}=\frac{-10}{2}
=-5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+6}{2*1}=\frac{2}{2}
=1
$