x+(x-1)=(x-2)+(x-3)+1=100

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Solution for x+(x-1)=(x-2)+(x-3)+1=100 equation: 



x+(x-1)=(x-2)+(x-3)+1=100

We move all terms to the left:

x+(x-1)-((x-2)+(x-3)+1)=0

We get rid of parentheses

x+x-((x-2)+(x-3)+1)-1=0



We calculate terms in parentheses: -((x-2)+(x-3)+1), so:

(x-2)+(x-3)+1

We get rid of parentheses

x+x-2-3+1

We add all the numbers together, and all the variables

2x-4

Back to the equation:

-(2x-4)



We add all the numbers together, and all the variables

2x-(2x-4)-1=0

We get rid of parentheses

2x-2x+4-1=0

We add all the numbers together, and all the variables

3!=0

There is no solution for this equation

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