x+(x-10)+(6+2x)=100

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Solution for x+(x-10)+(6+2x)=100 equation: 



x+(x-10)+(6+2x)=100

We move all terms to the left:

x+(x-10)+(6+2x)-(100)=0

We add all the numbers together, and all the variables

x+(x-10)+(2x+6)-100=0

We get rid of parentheses

x+x+2x-10+6-100=0

We add all the numbers together, and all the variables

4x-104=0

We move all terms containing x to the left, all other terms to the right

4x=104

x=104/4

x=26

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