x+(x-10)+2(x-10)=58

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Solution for x+(x-10)+2(x-10)=58 equation: 



x+(x-10)+2(x-10)=58

We move all terms to the left:

x+(x-10)+2(x-10)-(58)=0

We multiply parentheses

x+(x-10)+2x-20-58=0

We get rid of parentheses

x+x+2x-10-20-58=0

We add all the numbers together, and all the variables

4x-88=0

We move all terms containing x to the left, all other terms to the right

4x=88

x=88/4

x=22

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