x+(x-2)+(3+x+2)=20

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Solution for x+(x-2)+(3+x+2)=20 equation:


Simplifying
x + (x + -2) + (3 + x + 2) = 20

Reorder the terms:
x + (-2 + x) + (3 + x + 2) = 20

Remove parenthesis around (-2 + x)
x + -2 + x + (3 + x + 2) = 20

Reorder the terms:
x + -2 + x + (3 + 2 + x) = 20

Combine like terms: 3 + 2 = 5
x + -2 + x + (5 + x) = 20

Remove parenthesis around (5 + x)
x + -2 + x + 5 + x = 20

Reorder the terms:
-2 + 5 + x + x + x = 20

Combine like terms: -2 + 5 = 3
3 + x + x + x = 20

Combine like terms: x + x = 2x
3 + 2x + x = 20

Combine like terms: 2x + x = 3x
3 + 3x = 20

Solving
3 + 3x = 20

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-3' to each side of the equation.
3 + -3 + 3x = 20 + -3

Combine like terms: 3 + -3 = 0
0 + 3x = 20 + -3
3x = 20 + -3

Combine like terms: 20 + -3 = 17
3x = 17

Divide each side by '3'.
x = 5.666666667

Simplifying
x = 5.666666667

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