x+(x-3)+((x-3)-8)=72

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Solution for x+(x-3)+((x-3)-8)=72 equation: 



x+(x-3)+((x-3)-8)=72

We move all terms to the left:

x+(x-3)+((x-3)-8)-(72)=0

We get rid of parentheses

x+x+((x-3)-8)-3-72=0



We calculate terms in parentheses: +((x-3)-8), so:

(x-3)-8

We get rid of parentheses

x-3-8

We add all the numbers together, and all the variables

x-11

Back to the equation:

+(x-11)



We add all the numbers together, and all the variables

2x+(x-11)-75=0

We get rid of parentheses

2x+x-11-75=0

We add all the numbers together, and all the variables

3x-86=0

We move all terms containing x to the left, all other terms to the right

3x=86

x=86/3

x=28+2/3

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