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x+(x-3)+((x-3)-8)=72
We move all terms to the left:
x+(x-3)+((x-3)-8)-(72)=0
We get rid of parentheses
x+x+((x-3)-8)-3-72=0
We calculate terms in parentheses: +((x-3)-8), so:We add all the numbers together, and all the variables
(x-3)-8
We get rid of parentheses
x-3-8
We add all the numbers together, and all the variables
x-11
Back to the equation:
+(x-11)
2x+(x-11)-75=0
We get rid of parentheses
2x+x-11-75=0
We add all the numbers together, and all the variables
3x-86=0
We move all terms containing x to the left, all other terms to the right
3x=86
x=86/3
x=28+2/3
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