x+(x-5)+((x-5)-2)=333

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Solution for x+(x-5)+((x-5)-2)=333 equation: 



x+(x-5)+((x-5)-2)=333

We move all terms to the left:

x+(x-5)+((x-5)-2)-(333)=0

We get rid of parentheses

x+x+((x-5)-2)-5-333=0



We calculate terms in parentheses: +((x-5)-2), so:

(x-5)-2

We get rid of parentheses

x-5-2

We add all the numbers together, and all the variables

x-7

Back to the equation:

+(x-7)



We add all the numbers together, and all the variables

2x+(x-7)-338=0

We get rid of parentheses

2x+x-7-338=0

We add all the numbers together, and all the variables

3x-345=0

We move all terms containing x to the left, all other terms to the right

3x=345

x=345/3

x=115

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